The surface area of that portion of the surface z = √(4 – x2)

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The surface area of that portion of the surface z = √(4 – x²) that lies above the rectangle R in the xy-plane whose co-ordinates satisfy 0 ≤ x ≤ 1 and 0 ≤ y ≤ 4 is equal to

[A] 4 – π
[B] (3/4) π²
[C] {(√3)/5} π
[D] (4/3) π

The correct answer for The surface area of that portion of the surface z = √(4 – x²) that lies above the rectangle R in the XY-plane whose co-ordinates satisfy 0 ≤ x ≤ 1 and 0 ≤ y ≤ 4 is equal to is (4/3) π