What is the hydraulic conductivity of the aquifer

In a groundwater field test, a tracer took 8 hours to travel between two observation wells which are 56 m apart. The difference in water table

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In a groundwater field test, a tracer took 8 hours to travel between two observation wells which are 56 m apart. The difference in water table elevations in these wells was 0.70 m. The volume of the void of the aquifer is 30% of the total volume of the aquifer. What is the hydraulic conductivity of the aquifer, if the dynamic viscosity of water is 0.995 × 10-3 Ns/m2?





ANSWER= [A] 4.664 cm/s

Detailed Solution for Civil Engineering Exam

The tracer records the actual velocity of water

Vact = (56 * 100)/(8 * 60 * 60) = 60/36 cm/sec

Discharge Velocity, V = (n * Vact)

where,

n = Porosity = (Volume of voids/Total volume)

n = 0.30 (given)

V = (0.30* (7/36)) = 7/120 cm/sec

Hydraulic gradient (i) = [0.7/56] = 1.25 * 10-2

Coefficient of permeability or hydraulic

conductivity of aquifer (k) = (V/i)

k = 7/(120 * 1.25 * 10-2)

k = 14/3 cm/sec = 4.67 cm/sec


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